A) K
B) \[\frac{1}{K}\]
C) \[\frac{A}{{{d}^{2}}K}\]
D) \[\frac{{{d}^{2}}K}{A}\]
Correct Answer: A
Solution :
\[\Sigma mvr=\,({{l}_{system}})\omega \] Now, \[\Rightarrow \] As battery is disconnected, Q remains unaltered. So, \[mv\frac{l}{2}=\frac{(2m)\,{{(2l)}^{2}}}{12}\omega =\frac{2m(4{{l}^{2}})}{12}\omega \] \[\Rightarrow \] \[\omega =\frac{3v}{4l}\]You need to login to perform this action.
You will be redirected in
3 sec