A) \[h\]
B) \[\frac{3}{4}h\]
C) \[\frac{1}{2}h\]
D) \[\frac{1}{4}h\]
Correct Answer: C
Solution :
We have, \[10-\frac{\lambda }{2}=(2n)\frac{\lambda }{2},\,\,n=0,\,\,1,\,2,...\] \[10=(2n+1)\frac{\lambda }{2},\,n=0,\,1,\,\,2,...\] Output energy = 16 J By conservation of energy, \[\Rightarrow \] \[\lambda =\frac{20}{2n+1},\,\,n=0,\,\,1,\,\,2,...\]You need to login to perform this action.
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