A) \[M{{n}_{3}}{{O}_{4}}\]
B) \[Pb{{O}_{2}}\]
C) \[P{{b}_{3}}{{O}_{4}}\]
D) \[F{{e}_{2}}{{O}_{3}}\]
Correct Answer: B
Solution :
\[h{{d}_{w}}g={{h}_{w}}{{d}_{w}}g+{{h}_{o}}{{d}_{o}}g\] \[\therefore \] \[h={{h}_{w}}+\frac{{{h}_{o}}{{d}_{o}}}{{{d}_{w}}}\] Brown \[=100+\frac{400\times 0.9}{1}\]You need to login to perform this action.
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