\[A\xrightarrow{{{k}_{1}}}B\] Activation energy \[{{E}_{{{a}_{1}}}}\] |
\[A\xrightarrow{{{k}_{2}}}C\] Activation energy \[E{{\,}_{{{a}_{2}}}}\] |
A) \[{{k}_{2}}={{k}_{1}}{{e}^{-{{E}_{{{a}_{1}}}}/RT}}\]
B) \[{{k}_{2}}={{k}_{1}}{{e}^{-{{E}_{{{a}_{2}}}}/RT}}\]
C) \[{{k}_{1}}={{k}_{2}}{{e}^{-{{E}_{{{a}_{1}}}}/RT}}\]
D) \[{{k}_{1}}=2{{k}_{2}}{{e}^{{{E}_{{{a}_{2}}}}/RT}}\]
Correct Answer: A
Solution :
\[\theta ={{45}^{o}}\] \[n'=\frac{v}{v-{{v}_{s}}}\times n\] \[\Rightarrow \] (Since, \[\frac{n'}{n}=\frac{v}{v-{{v}_{s}}}\])You need to login to perform this action.
You will be redirected in
3 sec