A) 9.8
B) 98
C) 980
D) 9800
Correct Answer: C
Solution :
Emitter current is 2 mA, input resistance is \[400\,\,\Omega ,\] output resistance is \[400\,\,k\Omega =400\times {{10}^{3}}\Omega ,\] input voltage is \[2\times 400\,mV=800\,mV=0.800\,V\] and collector current \[{{I}_{C}}=0.98\times 2=1.96\,mA\]. Output or collector voltage is \[(1.96\times {{10}^{-3}})\times (400\times {{10}^{+3}})=784\,V\] Voltage amplification is, \[\frac{784}{0.800}=980\]You need to login to perform this action.
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