question_answer

In the circuit shown, the current in \[3\,\,\Omega \]resistor is

A)  1 A     

B)  \[\frac{30}{7}A\]

C)  \[\frac{5}{7}A\]                    

D)  Information insufficient

Correct Answer: C

Solution :

 Apply Kirchhoff's current law at junction having potential V. \[\frac{V-10}{2}+\frac{V-0}{6}+\frac{V-0}{2}=0\] \[\Rightarrow \]            \[V=\frac{30}{7}\,volt\] Both \[3\,\Omega \] resistors are connected in series, so the required current, \[i=\frac{V-0}{6}=\frac{5}{7}A\]