A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
\[{{A}_{1}},\,{{A}_{2}},\,{{A}_{3,}}...,\,{{A}_{2009}}\] and \[{{H}_{1}},\,{{H}_{2}},...,{{H}_{2009}}\] are AM and HM between a and b. Hence, \[{{A}_{1}}{{H}_{2009}}={{A}_{2}}{{H}_{2008}}=...={{A}_{1005}}{{H}_{1005}}=....\] \[={{A}_{2009}}{{H}_{1}}\] \[\therefore \] \[\frac{{{A}_{1006}}{{H}_{1004}}}{{{A}_{1004}}{{H}_{1006}}}=1\]You need to login to perform this action.
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