A) \[\frac{2}{\sqrt{3}}\]
B) \[\sqrt{3}\]
C) \[\frac{1}{\sqrt{3}}\]
D) \[\frac{\sqrt{3}}{2}\]
Correct Answer: C
Solution :
\[\Delta ABC\] is an equilateral triangle, \[AB=BC=CA=2\] units. \[AD,\,BE\] are internal angle biscetors meet at a point I. then, Point P will inside the triangle \[IAB\] Area of \[\Delta IAB=\frac{1}{3}\Delta ABC\] \[=\frac{1}{3}\,\times 4\times \frac{\sqrt{3}}{4}=\frac{1}{\sqrt{3}}\] unitsYou need to login to perform this action.
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