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JEE Main & Advanced Sample Paper JEE Main Sample Paper-44

  • question_answer
    Argon gas taken in a closed vessel was heated from \[-13{}^\circ C\] to \[13{}^\circ C\], the percentage increase in pressure inside the bulb is

    A)  11%                           

    B)  10%           

    C)  100%                         

    D)  110%

    Correct Answer: B

    Solution :

                  \[\frac{{{p}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}}{{{T}_{2}}}\] \[\frac{p}{260}=\frac{{{p}_{2}}}{286}\] \[1.1p={{p}_{2}}\] \[\therefore \] % increase \[=\frac{1.1\,p-p}{p}=\frac{0.1\,p}{p}\times 100=10%\]


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