A) \[h\] is continuous for all \[x\]
B) \[h\] is differentiable for all \[x\]
C) \[h'(a)=1,\,\,\forall x>1\]c
D) h is not differentiable at two values of \[x\]
Correct Answer: A
Solution :
Now we draw the graph \[y=-x,\,\,y=1\] and \[y={{x}^{2}}\] From graph it is clear that \[h\,(x)\] is continuous at all \[x\] and it not differentiable at \[x=-1,\,\,0,1\].You need to login to perform this action.
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