A) 4
B) 3
C) 2
D) 1
Correct Answer: A
Solution :
The given curve can be written as \[({{y}^{2}}+1)\,\,(x-1)=0\Rightarrow \,\,\,x=1\] \[({{y}^{2}}+2)\,(x-3)=0\,\Rightarrow \,\,x=3\] Hence, \[f(1+x)=f(1-x)\] ?(i) \[f(3+x)=f(3-x)\] ?(ii) From Eqs. (i) and (ii), we get \[f(x)=f(2-x)\] and \[f(x)=f(6-x)\] \[\Rightarrow \] \[f(2-x)=f(6-x)\] \[\Rightarrow \] \[f(x+4)\]You need to login to perform this action.
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