A) 600
B) 820
C) 840
D) 620
Correct Answer: C
Solution :
CALCULUS \[\square \] \[\square \] \[\square \] \[\square \] \[\square \] \[\square \] \[\square \] \[\square \] All C?s occur before all L?s is \[^{8}{{C}_{4}}=\frac{8!}{4!4!}=\frac{8\times 7\times 6\times 5}{24}=70\] Now, there are four places remaining. These places are filled by the letters (A, U, U, S). So, number of ways of filling those four places \[=\frac{4!}{2!}=12\] Total words \[=70\times 12=840\]You need to login to perform this action.
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