A) becomes half
B) remains the same
C) becomes 6 times
D) becomes 4 times
Correct Answer: C
Solution :
Given, the distance between two slits \[d'=\frac{d}{2}\] and the distance between screen and slit \[D'=3D\] We know that fringe width \[\beta =\frac{D\lambda }{d}\] Now, according to question \[\beta '=\frac{D'\lambda }{d'}\] \[\Rightarrow \] \[\beta '=\frac{3D\cdot \lambda }{d/2}\] \[\therefore \] \[\beta '=6\,\frac{D\lambda }{d}=6\beta \] \[\Rightarrow \] Final fringe width \[=6\times \] initial fringe width.
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