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JEE Main & Advanced Sample Paper JEE Main Sample Paper-45

  • question_answer
    Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is \[300\,\,m{{s}^{-1}}\]. What is the phase difference between the oscillations of two points?

    A)  \[\frac{\pi }{3}\]                                

    B)  \[\frac{2\pi }{3}\]

    C)  \[\pi \]                         

    D)  \[\frac{\pi }{6}\]

    Correct Answer: B

    Solution :

     Path difference between two points \[\Delta x=15-10=5\,\text{m}\] Time period, \[T=0.5\,s\Rightarrow \] frequency \[v=\frac{1}{T}=\frac{1}{0.05}=20\,\,Hz\] Velocity, \[v=300\,\,\text{m}{{\text{s}}^{-1}}\] \[\therefore \] Wavelength, \[\lambda =\frac{v}{v}=\,\frac{300}{20}=15\,m\] Hence, phase difference \[\Delta \phi =\frac{2\pi }{\lambda }\times \Delta x=\frac{2\pi }{15}\times 5=\frac{2\pi }{3}\]


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