A) the tension in the string GH is 6 g
B) the tension in the string GH is zero
C) the tension in string GH is\[\frac{21g}{4}\]
D) the 2 kg block remains in equilibrium
Correct Answer: C
Solution :
In equilibrium, just before the string AB is cut the tension in spring is 5 g. Just after the string AB is cut the spring force won't change but all blocks except of 5 kg start accelerating. Rough free body diagram is shown in figure. \[a=\frac{\text{Net}\,\text{pulling}\,\text{force}}{\text{Total}\,\text{mass}}\] \[=\frac{5g+g-g-2g}{4}=\frac{3g}{4}\] For 1 kg block (connected to spring) Free body diagram would be as shown \[5g+g-T=1\times \frac{3g}{4}\] \[T=6g-\frac{3g}{4}=\frac{21g}{4}\]You need to login to perform this action.
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