A) \[C{{H}_{3}}-C{{H}_{2}}-C\equiv CH\] and \[C{{H}_{2}}=CH-CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}-C\equiv C-C{{H}_{3}}\] and \[C{{H}_{3}}-CH=C=C{{H}_{2}}\]
C)
and 
D)
Correct Answer: A
Solution :
Since the compound gives ppt with ammoniacal \[AgN{{O}_{3}}\] and ammoniacal \[C{{u}_{2}}C{{l}_{2}},\] it must be a terminal alkyne. So its formula must be \[C{{H}_{3}}-C{{H}_{2}}-C\equiv CH\]. Its possible isomer which gives 1,4-dibromo-2-butene is 1,3-butadiene in conjugated diene system, 1, 4-addition product is major in comparison to 1, 2-addition product for butadiene.
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