A) 1%
B) 2%
C) 4%
D) 8%
Correct Answer: C
Solution :
\[\because \] \[N{{i}_{98}}{{O}_{100}}\] means total charge due to oxygen atoms \[=-2\times 100=-200\] \[\therefore \] Total charge due to Ni ions must be +200. Let \[N{{i}^{2+}}\] ions be \[x\]. \[\therefore \] \[N{{i}^{3+}}\] ions will be \[(98-x)\] \[\therefore \] \[(+2)\,(x)+\,(+3)\,(98-x)=+200\] \[\therefore \] \[x=94\] \[\therefore \] Fraction of Ni as \[N{{i}^{2+}}=\frac{94}{98}\times 100=96%\] And fraction of Ni as \[N{{i}^{3+}}=\frac{4}{98}\times 100=4%\]
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