| Statement I \[Sn\] on heating with dilute nitric acid gives \[Sn{{(N{{O}_{3}})}_{2}},\]\[N{{H}_{4}}N{{O}_{3}}\]and \[{{H}_{2}}\] gas. |
| Statement II \[Sn\] although a metal, does not produce Hg gas on reaction with dilute nitric acid. |
A) Statement I is true, Statement II is also true and Statement II is the correct explanation of Statement I.
B) Statement is true, Statement II is also true and Statement II is not the correct explanation of Statement I.
C) Statement I is true, Statement II is false.
D) Statement I is false, Statement II is true.
Correct Answer: D
Solution :
Statement I is wrong because in this reaction \[{{H}_{2}}O\] is produced instead of \[{{H}_{2}}\] gas, reason is correct because \[HN{{O}_{3}}\] being oxidizing in nature oxidizes \[{{H}_{2}}\] to \[{{H}_{2}}O\]. \[4\,Sn+10HN{{O}_{3}}\xrightarrow{\,}\,4\,Sn{{(N{{O}_{3}})}_{2}}\] dil \[+N{{H}_{4}}N{{O}_{3}}+3{{H}_{2}}O\]
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