A) 2
B) 3
C) 1
D) 8
Correct Answer: C
Solution :
\[f(x)={{x}^{3}}+{{x}^{2}}+4x+2\,\,\sin \,\,x=0\] \[f'(x)=3{{x}^{2}}+2x+4+2\,\,\cos \,\,x\] For \[\cos \,\,x=\pm \,1\] \[f'(x)=3{{x}^{2}}+2x+4\pm 2\] \[\Rightarrow \] \[(\because \,\,D={{b}^{2}}-4ac)\] Hence, only one solution exist, i.e., \[x=0\].You need to login to perform this action.
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