A) tautology
B) a contradiction
C) both a tautology and a contradiction
D) neither a tautology nor a contradiction
Correct Answer: B
Solution :
\[\therefore \]\[(p\wedge \sim q)\,\wedge \,(p\wedge q)\equiv \,(p\wedge \sim p)\wedge \,(\sim q\wedge q)\] \[\equiv f\,\wedge f=f\] Hence, it is a contradiction.You need to login to perform this action.
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