A) 338
B) 329
C) 330
D) 331
Correct Answer: B
Solution :
When we keep the toys of Ramya and Saumya together, the problem is to fixed the number of ways in which Ramya can take 4 toys out of 11 toys, not including the number of ways in which she takes her original 4 toys which can be done in \[^{11}{{C}_{4}}-1=\frac{11!}{4!7!}-1=329\]
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