A) \[1\times {{10}^{-5}}\]
B) \[2\times {{10}^{-5}}\]
C) \[1\times {{10}^{-5}}\,{{a}^{2}}\]
D) \[1\times {{10}^{-5}}\,\times \,\,{{a}^{-1}}\]
Correct Answer: A
Solution :
Since, s-orbital is spherically symmetrical hence the probability will remain the same.You need to login to perform this action.
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