A) \[\frac{2{{E}_{1}}}{{{N}_{0}}},\,\,\frac{2({{E}_{1}}-{{E}_{2}})}{{{N}_{0}}}\]
B) \[\frac{2{{E}_{1}}}{{{N}_{0}}},\,\,\frac{2{{E}_{2}}}{{{N}_{0}}}\]
C) \[\frac{{{E}_{1}}-{{E}_{2}}}{{{N}_{0}}},\,\,\frac{2{{E}_{1}}}{{{N}_{0}}}\]
D) None of these
Correct Answer: B
Solution :
\[\because \,\,X(g)\,\to \,{{X}^{+}}(g)\,+{{e}^{-}};\,\,\Delta H={{E}_{1}}\] for \[\frac{1}{2}\] mol \[\therefore \] \[IP=\frac{2{{E}_{1}}}{{{N}_{0}}}\] Again \[\because \] \[X(g)+{{e}^{-}}\to {{X}^{-}}(g),\] \[\Delta H=-{{E}_{2}}\] for \[\frac{1}{2}\] mole \[\therefore \] \[EA=\frac{2{{E}_{2}}}{{{N}_{0}}}\]You need to login to perform this action.
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