A) \[1\,\,m{{s}^{-2}}\]
B) \[2.5\,\,m{{s}^{-2}}\]
C) \[10\,\,m{{s}^{-2}}\]
D) \[5\,\,m{{s}^{-2}}\]
Correct Answer: D
Solution :
Net downward acceleration \[{{a}_{d}}=\frac{\text{Weight}-\text{friction force}}{\text{mass}}\] \[\Rightarrow \] \[{{a}_{d}}=\frac{(mg-\mu R)}{m}\](Area R = normal force) \[=\frac{60\times 10-0.5\times 600}{60}\] \[=\frac{300}{60}=5\,\,m{{s}^{-2}}\]You need to login to perform this action.
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