A) \[\frac{{{e}_{1}}}{{{e}_{2}}}l\sqrt{2gh}\]
B) \[\frac{{{e}_{1}}+1}{{{e}_{2}}+1}\sqrt{2gh}\]
C) \[\frac{{{e}_{1}}+{{e}_{2}}}{l}\sqrt{2gh}\]
D) \[\frac{{{e}_{1}}+1}{{{e}_{2}}-1}\sqrt{2gh}\]
Correct Answer: C
Solution :
After collision, the end A moves with a linear velocity of \[{{e}_{1}}\sqrt{2gh}\]. Whereas end B moves with a velocity of \[{{e}_{2}}\,\sqrt{2gh}\]. \[\therefore \] The relative velocity between the ends is \[V={{e}_{1}}\,\sqrt{2gh}-{{e}_{2}}\sqrt{2gh}\] The angular velocity, \[=\frac{V}{l}=\frac{{{e}_{1}}-{{e}_{2}}}{l}\,\sqrt{2gh}\]You need to login to perform this action.
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