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JEE Main & Advanced Sample Paper JEE Main Sample Paper-46

  • question_answer
    A block Q of mass M is placed on a frictionless horizontal surface AB and a body P of mass m is released on its frictionless slope. As P slides by a length L on this slope of inclination \[\theta \], the block Q would slide by a distance              

    A)  \[\frac{m}{M}L\,\cos \,\theta \]                     

    B)  \[\frac{m}{M+m}L\]

    C)  \[\frac{M+m}{mL\,\cos \,\theta }\]               

    D)  \[\frac{mL\,\cos \,\theta }{m+M}\]

    Correct Answer: D

    Solution :

     Here, the x-coordinate of centre of mass of the system remains unchanged when the mass m moved a distance \[L\cos \theta \], let the mass (m + M) moves a distance x in the backward direction. (from the theory of centre of mass, change in coordinate of centre of mass = 0) \[\therefore \]    \[(M+m)\,x-mL\,\,\cos \,\theta =0\] \[\therefore \]    \[x=\frac{mL\,\cos \,\,\theta }{m+M}\]


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