question_answer

Figure shows a network of a capacitor and resistors. The charge on capacitor in steadystate is

A)  \[4\,\mu C\]                

B)  \[6\,\mu C\]

C)  \[10\,\mu C\]              

D)  \[16\,\mu C\]

Correct Answer: D

Solution :

 Let the potential of the junction be V. then, \[\frac{6-V}{2}+\frac{4-V}{4}+\frac{8-V}{4}=0\] \[\Rightarrow \]            \[12-2V+4-V+8-V=0\] \[24=4V\] V = 6 volt \[\therefore \] Potential drop across capacitor \[=6-\,(-10)\] \[=16\,V\] \[\Rightarrow \] Charge on capacitor\[=16\,\mu C\]