JEE Main & Advanced Sample Paper JEE Main Sample Paper-46

  • question_answer
    Direction: According to the 6ohr model, the energy levels of a hydrogen atom can be found by making two assumptions.
    (i) The electrons move in a circular orbit and (ii) the angular momentum of the electron in the n\[th\]energy level is quantized to have a value,\[n\frac{h}{2\pi }\]. The levels calculated with a nuclear charge \[Ze\] deals with a single electron in the orbit are called hydrogenic levels. Assume that the two electrons in the ground, state of a helium atom occupy the corresponding lowest hydrogenic level.
    If for a hydrogen atom ionization temperature is T, the temperature at which He atomsionize completely (both electrons having left off the atom) would be

    A)  8T                                 

    B)  4T

    C)  6T                                 

    D)  2T

    Correct Answer: A

    Solution :

     As for atom,    \[\frac{5}{2}kT=13.6\]          ?(i) Energy required to remove two electrons from He must be greater than 54.4 eV. \[\frac{3}{2}kT'>54.4\]                      ?(ii) From Eqs. (i) and (ii), we get \[\frac{3T'}{5T}>\frac{54.4}{13.6}\] \[T'>\frac{20}{3}T\] \[T'>6.66T\] So, among the options \[T'\] can be 8T


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