A) \[\frac{qQ}{4\pi {{\varepsilon }_{0}}r}\]
B) \[\frac{qQ}{12\pi {{\varepsilon }_{0}}r}\]
C) \[\frac{qQ}{6\pi {{\varepsilon }_{0}}}\]
D) \[\frac{qQ}{2\pi {{\varepsilon }_{0}}r}\]
Correct Answer: C
Solution :
KE of -q at \[O=q({{V}_{0}}-{{V}_{p}})\] (consider the potential at the axial point, p is \[{{v}_{p}}\]) \[=\frac{2}{3}\,\frac{qQ}{4\pi {{\varepsilon }_{0}}r}=\frac{qQ}{6\pi {{\varepsilon }_{0}}r}\]You need to login to perform this action.
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