A) 8
B) 16
C) 24
D) 0
Correct Answer: B
Solution :
\[\int_{-1}^{15}{\sgn (\{x\})\,dx=}\,\int{\sgn \,(\{x-1\})dx}\](by property) \[\int_{0}^{16}{\sgn \,(x)\,dx}\]\[=16\,\int_{0}^{1}{1\,dx=16}\]
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