JEE Main & Advanced Sample Paper JEE Main Sample Paper-47

  • question_answer
    Figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is same at all points on   this curve and is equal to E. If the potential at A is V, then the potential at B is

    A)  \[V-ER\theta \]           

    B)  \[V-2ER\,\sin \,\frac{\theta }{2}\]

    C)  \[V+ER\theta \]                     

    D)  \[V+2ER\,\sin \,\frac{\theta }{2}\]

    Correct Answer: A

    Solution :

     As,      \[V=-\int{E\cdot dr}\] \[\Rightarrow \]            \[{{V}_{B}}-{{V}_{A}}=-ER\,\theta \] \[{{V}_{B}}=V-ER\,\theta \]

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