• # question_answer Figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is same at all points on   this curve and is equal to E. If the potential at A is V, then the potential at B is A)  $V-ER\theta$            B)  $V-2ER\,\sin \,\frac{\theta }{2}$ C)  $V+ER\theta$                      D)  $V+2ER\,\sin \,\frac{\theta }{2}$

As,      $V=-\int{E\cdot dr}$ $\Rightarrow$            ${{V}_{B}}-{{V}_{A}}=-ER\,\theta$ ${{V}_{B}}=V-ER\,\theta$