• # question_answer An equilateral triangular loop having a resistance R and length of each side$l$is placed in a magnetic field which is varying at $\frac{dB}{dt}=1T/s$. The induced current in the loop will be A)  $\frac{\sqrt{3}}{4}\frac{{{l}^{2}}}{R}$ B)  $\frac{4}{\sqrt{3}}\frac{{{l}^{2}}}{R}$ C)  $\frac{\sqrt{3}}{4}\frac{R}{{{l}^{2}}}$             D)  $\frac{4}{\sqrt{3}}\frac{R}{{{l}^{2}}}$

With the help of information?s in the equation. $\phi =\frac{\sqrt{3}}{4}{{I}^{2}}B,\,\,\Rightarrow \,\,\varepsilon =\left| \frac{d\phi }{dt} \right|=\frac{\sqrt{3}}{4}{{I}^{2}}\,\frac{dB}{dt},$ $\therefore$    $I=\frac{\pi }{R}=\,\frac{\sqrt{3}{{I}^{2}}}{4R}$