A) \[\frac{aL}{2g}\]
B) \[\frac{gL}{2a}\]
C) \[\frac{gL}{a}\]
D) \[\frac{aL}{g}\]
Correct Answer: D
Solution :
Newton?s equations are, \[A\Delta p\,\,\sin \theta \,=ma\] and \[A\Delta p\,\,\cos \theta \,=mg\] By Eqs. (i) and (ii), we get \[\tan \,\theta =\frac{a}{g}=\frac{h}{L}\] or \[h=\frac{aL}{g}\]You need to login to perform this action.
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