• # question_answer The correct set of quantum numbers for the last electron of P in${{H}_{3}}P{{O}_{4}}$ is A)  $3,\,\,0,\,\,0,\,+\frac{1}{2}$             B)  $3,\,1,\,\,-1,\,+\frac{1}{2}$ C)  $21-1-\frac{1}{2}$               D)  $3,\,1,\,-1,\,-\frac{1}{2}$

In ${{H}_{3}}P{{O}_{4}},$ P is present as ${{P}^{5+}}$${{P}^{5+}}=1{{s}^{2}},\,\,2{{s}^{2}},\,\,2{{p}^{6}}$ Thus, the last electron enters in $2{{p}^{6}}$ For $n=2,\,\,I=1,\,\,m=-1$ and $s=-\frac{1}{2}$