question_answer

The correct set of quantum numbers for the last electron of P in\[{{H}_{3}}P{{O}_{4}}\] is

A)  \[3,\,\,0,\,\,0,\,+\frac{1}{2}\]            

B)  \[3,\,1,\,\,-1,\,+\frac{1}{2}\]

C)  \[21-1-\frac{1}{2}\]              

D)  \[3,\,1,\,-1,\,-\frac{1}{2}\]

Correct Answer: C

Solution :

 In \[{{H}_{3}}P{{O}_{4}},\] P is present as \[{{P}^{5+}}\]\[{{P}^{5+}}=1{{s}^{2}},\,\,2{{s}^{2}},\,\,2{{p}^{6}}\] Thus, the last electron enters in \[2{{p}^{6}}\] For \[n=2,\,\,I=1,\,\,m=-1\] and \[s=-\frac{1}{2}\]