A) 12 m/s
B) 6.6 m/s
C) 4.2 m/s
D) 5.9 m/s
Correct Answer: D
Solution :
As \[{{v}^{'}}=1.04\,v\] \[=v\left( \frac{300+{{v}_{0}}}{300-{{v}_{0}}} \right)\] \[\Rightarrow \] \[300+{{v}_{0}}=300\times 1.04-1.04\,{{v}_{0}}\] or \[2.04\,{{v}_{0}}=0.04\times 300\] \[\therefore \] \[{{v}_{0}}=5.88\,m/s\simeq 5.9\,m/s\]You need to login to perform this action.
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