A) \[\sqrt{\frac{3T}{g(2d-\rho )}}\]
B) \[\sqrt{\frac{3T}{g(d-\rho )}}\]
C) \[\sqrt{\frac{6T}{g(2d-\rho )}}\]
D) \[\sqrt{\frac{6T}{g(d-\rho )}}\]
Correct Answer: A
Solution :
For equilibrium of drop, \[\frac{2}{3}\pi {{R}^{3}}\,\rho g+2\pi RT=\frac{4}{3}\pi {{R}^{3}}dg\] \[\Rightarrow \] \[2RT=\frac{2}{3}{{R}^{3}}g\,(2d-\rho )\] \[\therefore \] \[R=\sqrt{\frac{3T}{(2d-\rho )g}}\]You need to login to perform this action.
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