A) \[x-y=0\]
B) \[x+y=0\]
C) \[x-y=2\]
D) \[x+y=1\]
Correct Answer: B
Solution :
Given curve, \[y={{x}^{2}}-x\] When \[x-y=0\] or \[y=x\] from Eq. (i) \[{{x}^{2}}-2x=0\] its discriminant \[D\ne 0\] When \[x+y=0\] or \[y=-x\] from Eq. (i) \[{{x}^{2}}=0\] its discrimanat D = 0 Hence, \[x+y=0\] is a tangent.You need to login to perform this action.
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