A) \[(1,\,\,-3)\]
B) \[(2,\,\,2)\]
C) \[(-2,\,\,4)\]
D) \[(1,\,\,2)\]
Correct Answer: B
Solution :
\[\because \] \[x={{t}^{2}}+1\] and \[y=2t\] \[\Rightarrow \] \[x={{\left( \frac{y}{2} \right)}^{2}}+1\] \[\Rightarrow \] \[{{y}^{2}}=4(x-1)\] Also, \[x=2s\] and \[y=2/s\] \[\therefore \] \[xy=4\] From Eqs. (i) and (ii) we get \[x=2\] \[\Rightarrow \] \[y=\frac{4}{2}=2\] Hence, point is (2, 2).You need to login to perform this action.
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