A) \[\frac{E}{2R}amp,\frac{E}{2}volt\]
B) \[\frac{E}{9R}amp,E/2volt\]
C) \[\frac{E}{3R}amp,\frac{E}{4}volt\]
D) \[\frac{E}{9R}amp,E/4volt\]
Correct Answer: A
Solution :
The circuit in steady state is shown in figure. Capacitor would be open circuit while inductor would be short circuited.You need to login to perform this action.
You will be redirected in
3 sec