A) \[\frac{Qd\ell }{8{{\pi }^{2}}{{\in }_{0}}{{R}^{3}}}\]
B) \[\frac{Q}{4\pi {{\in }_{0}}{{R}^{2}}}\]
C) zero
D) can't be determined
Correct Answer: A
Solution :
Here to solve this quations we can use principle of superposition. The given structure can be considered as combination of two as shown in figure. \[{{\vec{E}}_{at}}\] (due to given structure) \[={{\vec{E}}_{atO}}(due\,to\,l)-{{E}_{atO}}(due\,to\,all)\]\[E=\frac{dq}{4\pi {{\in }_{0}}{{R}^{2}}}\]towards dl. \[=\frac{Q/2\pi R\times d\ell }{4\pi {{\in }_{0}}{{R}^{2}}}=\frac{Qd\ell }{8{{\pi }^{2}}{{\in }_{0}}{{R}^{3}}}\]You need to login to perform this action.
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