A) \[C{{H}_{3}}-CH_{2}^{-}>NH_{2}^{-}>H-C\equiv {{C}^{-}}>O{{H}^{-}}\]
B) \[H-C\equiv {{C}^{-}}>C{{H}_{3}}-CH_{2}^{-}>NH_{2}^{-}>O{{H}^{-}}\]
C) \[O{{H}^{-}}>NH_{2}^{-}>H-C\equiv {{C}^{-}}>C{{H}_{3}}-CH_{2}^{-}\]
D) \[NH_{2}^{-}>H-C\equiv {{C}^{-}}>O{{H}^{-}}>C{{H}_{3}}-CH_{2}^{-}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}CH_{2}^{-}>NH_{2}^{-}>H-C\equiv {{C}^{-}}>H{{O}^{-}}\] It is because the order of acid - strength of their conjugate acid is\[C{{H}_{3}}C{{H}_{3}}<N{{H}_{3}}<H-C\]\[\equiv C-H<{{H}_{2}}O:\] Acid strength.You need to login to perform this action.
You will be redirected in
3 sec