A) \[M{{n}_{2}}{{O}_{3}}\]
B) \[Mn{{O}_{2}}\]
C) \[Mn{{O}_{4}}\]
D) \[MnO_{4}^{2-}\]
Correct Answer: B
Solution :
The equivalent mass will be half of molecular mass if change in oxidation number is 2. \[\overset{+2}{\mathop{MnS{{O}_{4}},}}\,\overset{+3}{\mathop{M{{n}_{2}}{{O}_{3}},}}\,\overset{+4}{\mathop{Mn{{O}_{2}},}}\,\overset{+8}{\mathop{Mn{{O}_{4}},}}\,\overset{+6}{\mathop{MnO_{4}^{2-}}}\,\] \[\overset{+2}{\mathop{MnS{{O}_{4}}}}\,\xrightarrow[{}]{{}}\overset{+4}{\mathop{Mn{{O}_{2}}}}\,\]
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