JEE Main & Advanced Sample Paper JEE Main Sample Paper-4

  • question_answer
    The equivalent mass of \[MnS{{O}_{4}}\] is half of its molecular mass when it is converted to

    A) \[M{{n}_{2}}{{O}_{3}}\]               

    B) \[Mn{{O}_{2}}\]

    C) \[Mn{{O}_{4}}\]                              

    D) \[MnO_{4}^{2-}\]

    Correct Answer: B

    Solution :

    The equivalent mass will be half of molecular mass if change in oxidation number is 2. \[\overset{+2}{\mathop{MnS{{O}_{4}},}}\,\overset{+3}{\mathop{M{{n}_{2}}{{O}_{3}},}}\,\overset{+4}{\mathop{Mn{{O}_{2}},}}\,\overset{+8}{\mathop{Mn{{O}_{4}},}}\,\overset{+6}{\mathop{MnO_{4}^{2-}}}\,\] \[\overset{+2}{\mathop{MnS{{O}_{4}}}}\,\xrightarrow[{}]{{}}\overset{+4}{\mathop{Mn{{O}_{2}}}}\,\]

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