A) Fv
B) mav
C) (F+ma)v
D) (ma-f)v
Correct Answer: C
Solution :
Let \[{{F}_{e}}\] is the constant force exerted by engine then \[{{F}_{e}}-F=ma\Rightarrow {{F}_{e}}=F+ma\] Power i.e. the rate at which engine is doing work is, \[P={{F}_{e}}v=(F+ma)v\]You need to login to perform this action.
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