A) \[\frac{1}{2}\]
B) \[\frac{49}{101}\]
C) \[\frac{50}{101}\]
D) \[\frac{51}{101}\]
Correct Answer: D
Solution :
Here \[n=100,p=p,q=1-p\] Given, P(50) = P(5 \[\Rightarrow \]\[^{100}{{C}_{50}}{{p}^{50}}{{(1-p)}^{50}}{{=}^{10}}{{C}_{51}}{{p}^{51}}{{(1-p)}^{49}}\] \[\Rightarrow \]\[\frac{100!}{50!50!}(1-p)=\frac{100!}{51!49!}p\]\[\Rightarrow \]\[51(1-p)=50p\] \[\Rightarrow \]\[p=\frac{51}{101}\]You need to login to perform this action.
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