JEE Main & Advanced Sample Paper JEE Main Sample Paper-4

  • question_answer
    When propionic acid is treated with aqueous sodium bicarbonate, \[C{{O}_{2}}\]is liberated. The C from \[C{{O}_{2}}\]comes from.

    A)  methyl group         

    B)  carboxylic acid group

    C)  methylene group      

    D)  bicarbonate

    Correct Answer: D

    Solution :

    Carboxylic acids reacts with weaker bases such as bicarbonates producing \[C{{O}_{2}}.\] The \[C{{O}_{2}}\] evolved comes from \[NaHC{{O}_{3}},\] not from carboxylic group as shown below.

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