• # question_answer In which of the following reaction ${{H}_{2}}{{O}_{2}}$ is a reducing agent? A) $2FeC{{l}_{2}}+2HCl+{{H}_{2}}{{O}_{2}}\to 2FeC{{l}_{3}}+2{{H}_{2}}O$ B) $C{{l}_{2}}+{{H}_{2}}{{O}_{2}}\to 2HCl+{{O}_{2}}$ C) $2Hl+{{H}_{2}}{{O}_{2}}\to 2{{H}_{2}}O+{{l}_{2}}$ D) ${{H}_{2}}S{{O}_{3}}+{{H}_{2}}{{O}_{2}}\to {{H}_{2}}S{{O}_{4}}+{{H}_{2}}O$

$C{{l}_{2}}+{{H}_{2}}{{\overset{-1}{\mathop{O}}\,}_{2}}\to 2HCl+{{\overset{0}{\mathop{O}}\,}_{2}}$Oxidation state of oxygen changes from -1 $({{H}_{2}}{{O}_{2}})$ to zero $({{O}_{2}})$ i.e., ${{H}_{2}}{{O}_{2}}$ getting oxidised and acting as reducing agent.