A) contradiction
B) tautology
C) equivalent to \[\tilde{\ }(p\Rightarrow q)\]
D) None of these
Correct Answer: D
Solution :
P | q | \[\tilde{\ }q\] | \[p\wedge \tilde{\ }q\] | \[\tilde{\ }(p\wedge \tilde{\ }q)\] | \[p\to \tilde{\ }(p\wedge \tilde{\ }q)\] |
T | F | T | T | F | F |
F | T | F | F | T | T |
\[\Rightarrow \] | |||||
T | T | F | F | T | T |
F | F | T | F | T | T |
You need to login to perform this action.
You will be redirected in
3 sec