A)
B)
C)
D)
Correct Answer: B
Solution :
Tangential acceleration\[\frac{{{d}^{2}}}{d{{t}^{2}}}={{k}_{1}}\] (constant) \[\Rightarrow \]\[v={{k}_{1}}t+c\] This is a equation for uniform acceleration. Normal acceleration\[\frac{{{v}^{2}}}{r}={{k}_{2}}\] \[\Rightarrow \]\[\frac{{{({{k}_{1}}t+c)}^{2}}}{r}={{k}_{2}}\] \[r=\frac{{{({{k}_{1}}t+c)}^{2}}}{{{k}_{2}}}={{(\alpha t+\beta )}^{2}}\], which is parabola. [Here, r = radius is always positive]You need to login to perform this action.
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