A) 6.25 A, 3.75 V
B) 3.00 A, 5 V
C) 3.75 A, 3.75V
D) 3.75 A, 6.25 V
Correct Answer: B
Solution :
\[{{R}_{eq}}\]of the circuit\[\frac{{{R}_{1}}\times {{R}_{2}}}{{{R}_{1}}+{{R}_{2}}}+{{R}_{3}}\] =\[\frac{5\times 15}{5+15}+\frac{125}{100}\] \[=\frac{75}{20}+\frac{5}{4}=5\Omega \] \[l=\frac{E}{{{R}_{eq}}}=\frac{20}{5}4A\] Current in\[{{R}_{1}}=\frac{l{{R}_{2}}}{{{R}_{1}}+{{R}_{2}}}=3\]A Potential difference across R\[{{R}_{3}}=l{{R}_{2}}=5\]VYou need to login to perform this action.
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